CAT Quantitative Ability Questions | CAT TIme, Speed, Distance and Work questions
CAT/1996
Question . 133
In a mile race, Akshay can be given a start of 128 metres by Bhairav. If Bhairav can give Chinmay a start of 4 metres in a 100 metres dash, then who out of Akshay and Chinmay will win a race of one and a half mile, and what will be the final lead given by the winner to the loser? (one mile is 1600 metres)
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Explanatory Answer
Method of solving this CAT Quantitative Ability Question from TIme, Speed, Distance and Work question
(d) When Bhairav covers 1600m, Akshay covers (1600 – 128) m.
So, when Bhairav covers (1600/16) = 100m, Akshay covers (128/16) m = 8 m less.
When Bhairav covers 100m. Chinmay covers (100 – 4) = 96 m
Thus, the ratio in which Akshay and Chinmay cover distances is 92 : 96.
In 96 m, Chinmay gains (96 – 92) = 4m over Akshay. So in 1.5 miles, Chinmay gains 100 m = (1/16) miles over Akshay