CAT Quantitative Ability Questions | CAT Averages, Ratio & Proportion questions
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CAT/2017.2
Question . 62
Consider three mixtures - the first having water and liquid A in the ratio 1 : 2, the second having water and liquid B in the ratio 1 : 3, and the third having water and liquid C in the ratio 1 : 4. These three mixtures of A, B, and C, respectively, are further mixed in the proportion 4 : 3 : 2. Then the resulting mixture has
Explanatory Answer
Method of solving this CAT Quantitative Ability Question from Averages, Ratio & Proportion question
Correct Option: C
Liquid 1 (L1) - W : A = 1 : 2
Liquid 2 (L2) - W : B = 1 : 3
Liquid 3 (L3) - W : C = 1 : 4
Liquids are mixed in the ratio of L1 : L2 : L3 = 4 : 3 : 2
Multiplying the ratio with LCM of 3, 4, and 5 which is 60
L1 : L2 : L3 = 240 : 180 : 120
Quantity of water in the mixture = 12×240+14×180+15×120 = 120 + 45 + 24 = 189
Quantity of total mixture = 240 + 180 + 120 = 540
Concentration of water in the final solution = 135540 = 7/20 = 0.35, which is greater than 13
Hence, concentration of water in the final mixture is more than that in the sample B.
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